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根因: Experience 结构体没有 tool_used 字段,PatternAggregator 从 context 字段提取工具名(语义混淆),导致工具信息不准确。 修复: - experience_store.rs: Experience 添加 tool_used: Option<String> 字段 (#[serde(default)] 兼容旧数据),Experience::new() 初始化为 None - experience_extractor.rs: persist_experiences() 从 ExperienceCandidate 的 tools_used[0] 填充 tool_used,同时填充 industry_context - pattern_aggregator.rs: 改用 tool_used 字段提取工具名,不再误用 context - store_experience() 将 tool_used 加入 keywords 提升搜索命中率
246 lines
7.7 KiB
Rust
246 lines
7.7 KiB
Rust
//! 经验模式聚合器
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//! 收集同一 pain_pattern 下的所有 Experience,找出共同步骤
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//! 用于 L2 技能进化触发判断
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use std::collections::HashMap;
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use crate::experience_store::{Experience, ExperienceStore};
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use zclaw_types::Result;
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/// 聚合后的经验模式
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#[derive(Debug, Clone)]
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pub struct AggregatedPattern {
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pub pain_pattern: String,
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pub experiences: Vec<Experience>,
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pub common_steps: Vec<String>,
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pub total_reuse: u32,
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pub tools_used: Vec<String>,
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pub industry_context: Option<String>,
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}
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/// 经验模式聚合器
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/// 从 ExperienceStore 中收集高频复用的模式,作为 L2 技能生成的输入
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pub struct PatternAggregator {
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store: ExperienceStore,
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}
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impl PatternAggregator {
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pub fn new(store: ExperienceStore) -> Self {
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Self { store }
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}
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/// 查找可固化的模式:reuse_count >= threshold 的经验
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pub async fn find_evolvable_patterns(
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&self,
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agent_id: &str,
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min_reuse: u32,
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) -> Result<Vec<AggregatedPattern>> {
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let all = self.store.find_by_agent(agent_id).await?;
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let mut grouped: HashMap<String, Vec<Experience>> = HashMap::new();
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for exp in all {
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if exp.reuse_count >= min_reuse {
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grouped
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.entry(exp.pain_pattern.clone())
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.or_default()
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.push(exp);
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}
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}
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let mut patterns = Vec::new();
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for (pattern, experiences) in grouped {
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let total_reuse: u32 = experiences.iter().map(|e| e.reuse_count).sum();
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let common_steps = Self::find_common_steps(&experiences);
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// 从 tool_used 字段提取工具名
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let tools: Vec<String> = experiences
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.iter()
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.filter_map(|e| e.tool_used.clone())
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.filter(|s| !s.is_empty())
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.collect::<std::collections::HashSet<_>>()
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.into_iter()
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.collect();
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let industry = experiences
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.iter()
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.filter_map(|e| e.industry_context.clone())
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.next();
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patterns.push(AggregatedPattern {
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pain_pattern: pattern,
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experiences,
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common_steps,
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total_reuse,
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tools_used: tools,
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industry_context: industry,
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});
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}
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// 按 reuse 排序
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patterns.sort_by(|a, b| b.total_reuse.cmp(&a.total_reuse));
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Ok(patterns)
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}
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/// 找出多条经验中共同的解决步骤
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fn find_common_steps(experiences: &[Experience]) -> Vec<String> {
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if experiences.is_empty() {
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return Vec::new();
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}
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if experiences.len() == 1 {
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return experiences[0].solution_steps.clone();
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}
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// 取所有经验的交集步骤
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let mut step_counts: HashMap<String, u32> = HashMap::new();
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for exp in experiences {
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for step in &exp.solution_steps {
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*step_counts.entry(step.clone()).or_insert(0) += 1;
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}
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}
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let threshold = experiences.len() as f32 * 0.5; // 出现在 50%+ 的经验中
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let mut common: Vec<_> = step_counts
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.into_iter()
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.filter(|(_, count)| (*count as f32) >= threshold)
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.map(|(step, _)| step)
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.collect();
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common.dedup();
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common
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}
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}
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#[cfg(test)]
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mod tests {
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use super::*;
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use std::sync::Arc;
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#[test]
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fn test_find_common_steps_empty() {
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let steps = PatternAggregator::find_common_steps(&[]);
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assert!(steps.is_empty());
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}
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#[test]
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fn test_find_common_steps_single() {
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let exp = Experience::new(
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"a",
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"packaging",
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"ctx",
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vec!["step1".into(), "step2".into()],
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"ok",
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);
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let steps = PatternAggregator::find_common_steps(&[exp]);
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assert_eq!(steps.len(), 2);
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}
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#[test]
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fn test_find_common_steps_multiple() {
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let exp1 = Experience::new(
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"a",
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"packaging",
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"ctx",
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vec!["step1".into(), "step2".into(), "step3".into()],
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"ok",
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);
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let exp2 = Experience::new(
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"a",
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"packaging",
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"ctx",
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vec!["step1".into(), "step2".into(), "step4".into()],
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"ok",
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);
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// step1 and step2 appear in both (100% >= 50%)
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let steps = PatternAggregator::find_common_steps(&[exp1, exp2]);
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assert!(steps.contains(&"step1".to_string()));
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assert!(steps.contains(&"step2".to_string()));
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}
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#[tokio::test]
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async fn test_find_evolvable_patterns_filters_low_reuse() {
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let viking = Arc::new(crate::VikingAdapter::in_memory());
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let store = ExperienceStore::new(viking);
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// 经验 1: reuse_count = 0 (低于阈值)
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let mut exp_low = Experience::new(
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"agent-1",
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"low reuse task",
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"ctx",
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vec!["step".into()],
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"ok",
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);
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exp_low.reuse_count = 0;
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store.store_experience(&exp_low).await.unwrap();
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// 经验 2: reuse_count = 5 (高于阈值)
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let mut exp_high = Experience::new(
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"agent-1",
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"high reuse task",
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"ctx",
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vec!["step1".into()],
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"ok",
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);
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exp_high.reuse_count = 5;
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store.store_experience(&exp_high).await.unwrap();
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let aggregator = PatternAggregator::new(store);
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let patterns = aggregator.find_evolvable_patterns("agent-1", 3).await.unwrap();
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assert_eq!(patterns.len(), 1);
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assert_eq!(patterns[0].pain_pattern, "high reuse task");
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assert_eq!(patterns[0].total_reuse, 5);
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}
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#[tokio::test]
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async fn test_find_evolvable_patterns_groups_by_pain() {
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let viking = Arc::new(crate::VikingAdapter::in_memory());
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let store = ExperienceStore::new(viking);
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let mut exp1 = Experience::new(
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"agent-1",
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"report generation",
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"ctx1",
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vec!["query db".into(), "format".into()],
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"ok",
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);
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exp1.reuse_count = 3;
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store.store_experience(&exp1).await.unwrap();
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// Same pain_pattern → same URI → overwrites, so use a slightly different hash
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// Actually since URI is deterministic on pain_pattern, we can only have one per pattern
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// This is by design: one experience per pain_pattern (latest wins)
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let patterns = aggregator_fixtures::make_patterns_with_same_pain().await;
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assert_eq!(patterns.len(), 1);
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}
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mod aggregator_fixtures {
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use super::*;
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pub async fn make_patterns_with_same_pain() -> Vec<AggregatedPattern> {
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let viking = Arc::new(crate::VikingAdapter::in_memory());
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let store = ExperienceStore::new(viking);
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let mut exp = Experience::new(
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"agent-1",
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"report generation",
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"ctx1",
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vec!["query db".into(), "format".into()],
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"ok",
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);
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exp.reuse_count = 3;
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store.store_experience(&exp).await.unwrap();
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let aggregator = PatternAggregator::new(store);
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aggregator.find_evolvable_patterns("agent-1", 2).await.unwrap()
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}
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}
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#[tokio::test]
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async fn test_find_evolvable_patterns_empty() {
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let viking = Arc::new(crate::VikingAdapter::in_memory());
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let store = ExperienceStore::new(viking);
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let aggregator = PatternAggregator::new(store);
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let patterns = aggregator.find_evolvable_patterns("unknown-agent", 3).await.unwrap();
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assert!(patterns.is_empty());
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}
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}
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